Roman To Numbers

          
Problem Statement
          example, 2 is written as II in Roman numerals, just two
          one's added together. 12 is written as XII, which is
          simply x + II The number 27 is written as XXVII, which 
          is XX + V + II
          Roman numerals are usually written largest to smallest
          from left to right. However, the numeral for four is
          not IIII. Instead, the number four is written as IV.
          Because the one is before the five we subtract it making
          four. The same principle applies to the number nine,
          which is written as IX. There are six instances where
          subtraction is used:
          I can be placed before V (5) and X (10) to make 4 and 9.
          X can be placed before L (50) and C (100) to make 40 and 90.
          C can be placed before D (500) and M (1000) to make 400 and 900.
          Given an integer, convert it to a roman numeral.
          
          
Example
          Exercise-1
          Input: LXI
          Output : 61
          
          Exercise-2
          Input: MXI
          Output: 1011
          
          

        

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Java code :--

 
         

import java.util.HashMap; 
import java.util.Map; 
import java.util.Scanner; 
 
public class MINtech { 
 
    // Function to convert a Roman numeral to an integer 
    public static int romanToInt(String s) { 
        // Create a map to store the values of Roman numerals 
        Map romanMap = new HashMap<>(); 
        romanMap.put('I', 1); 
        romanMap.put('V', 5); 
        romanMap.put('X', 10); 
        romanMap.put('L', 50); 
        romanMap.put('C', 100); 
        romanMap.put('D', 500); 
        romanMap.put('M', 1000); 
 
        // Initialize variables to store the result and the previous value 
        int result = 0; 
        int prevValue = 0; 
 
        // Iterate through the Roman numeral from right to left 
        for (int i = s.length() - 1; i >= 0; i--) { 
            // Get the numeric value of the current Roman numeral character 
            int value = (int) romanMap.get(s.charAt(i)); 
 
            // Check if the current value is less than the previous value 
            if (value < prevValue) { 
                // If yes, subtract the current value from the result 
                result -= value; 
            } else { 
                // If no, add the current value to the result 
                result += value; 
            } 
 
            // Update the previous value for the next iteration 
            prevValue = value; 
        } 
 
        // Return the final result 
        return result; 
    } 
 
    public static void main(String[] args) { 
        // Create a scanner to take user input 
        Scanner scanner = new Scanner(System.in); 
 
        // Get user input for a Roman numeral 
        System.out.print("Enter a Roman numeral: "); 
        String userInputRoman = scanner.nextLine(); 
 
        // Convert Roman numeral to integer and print the result 
        int integerResult = romanToInt(userInputRoman); 
        System.out.println("Integer: " + integerResult); 
 
        // Close the scanner to avoid resource leaks 
        scanner.close(); 
    } 
} 

         

Output

      Enter a Roman numeral: LXI
      Integer: 61

      Enter a Roman numeral: MXI
      Integer: 1011
  
        

Python code :---

  
       

def roman_to_int(s): 
    # Create a dictionary to map Roman numeral characters to their numeric values 
    roman_map = {'I': 1, 'V': 5, 'X': 10, 'L': 50, 'C': 100, 'D': 500, 'M': 1000} 
 
    # Initialize variables to store the result and the previous value 
    result = 0 
    prev_value = 0 
 
    # Iterate through the Roman numeral from right to left 
    for char in reversed(s): 
        # Get the numeric value of the current Roman numeral character 
        value = roman_map[char] 
 
        # Check if the current value is less than the previous value 
        if value < prev_value: 
            # If yes, subtract the current value from the result 
            result -= value 
        else: 
            # If no, add the current value to the result 
            result += value 
 
        # Update the previous value for the next iteration 
        prev_value = value 
 
    # Return the final result 
    return result 
 
if __name__ == "__main__": 
    # Get user input for a Roman numeral 
    user_input_roman = input("Enter a Roman numeral: ") 
 
    # Convert Roman numeral to integer and print the result 
    integer_result = roman_to_int(user_input_roman) 
    print("Integer:", integer_result) 

       
 

Output

      Enter a Roman numeral: LXI
      Integer: 61

      Enter a Roman numeral: MXI
      Integer: 1011